50 lines
2.3 KiB
SQL
50 lines
2.3 KiB
SQL
-- Returns one row per system, containing info about latest switch + array of member IDs (for future joins)
|
|
create view system_last_switch as
|
|
select systems.id as system,
|
|
last_switch.id as switch,
|
|
last_switch.timestamp as timestamp,
|
|
array(select member from switch_members where switch_members.switch = last_switch.id) as members
|
|
from systems
|
|
inner join lateral (select * from switches where switches.system = systems.id order by timestamp desc limit 1) as last_switch on true;
|
|
|
|
-- Returns one row for every current fronter in a system, w/ some member info
|
|
create view system_fronters as
|
|
select
|
|
systems.id as system_id,
|
|
last_switch.id as switch_id,
|
|
last_switch.timestamp as switch_timestamp,
|
|
members.id as member_id,
|
|
members.hid as member_hid,
|
|
members.name as member_name
|
|
from systems
|
|
-- TODO: is there a more efficient way of doing this search? might need to index on timestamp if we haven't in prod
|
|
inner join lateral (select * from switches where switches.system = systems.id order by timestamp desc limit 1) as last_switch on true
|
|
|
|
-- change to left join to handle memberless switches?
|
|
inner join switch_members on switch_members.switch = last_switch.system
|
|
inner join members on members.id = switch_members.member
|
|
-- return them in order of the switch itself
|
|
order by switch_members.id;
|
|
|
|
create view member_list as
|
|
select members.*,
|
|
-- Find last message ID
|
|
-- max(mid) does full table scan, order by/limit uses index (dunno why, but it works!)
|
|
(select mid from messages where messages.member = members.id order by mid desc nulls last limit 1) as last_message,
|
|
|
|
-- Find last switch timestamp
|
|
(
|
|
select max(switches.timestamp)
|
|
from switch_members
|
|
inner join switches on switches.id = switch_members.switch
|
|
where switch_members.member = members.id
|
|
) as last_switch_time,
|
|
|
|
-- Extract month/day from birthday and "force" the year identical (just using 4) -> month/day only sorting!
|
|
case when members.birthday is not null then
|
|
make_date(
|
|
4,
|
|
extract(month from members.birthday)::integer,
|
|
extract(day from members.birthday)::integer
|
|
) end as birthday_md
|
|
from members; |