71 lines
2.2 KiB
Python
71 lines
2.2 KiB
Python
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import errno
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import os
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import re
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from collections.abc import Callable
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from functools import cache
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from veilid.json_api import _JsonVeilidAPI
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import veilid
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ERRNO_PATTERN = re.compile(r"errno (\d+)", re.IGNORECASE)
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class VeilidTestConnectionError(Exception):
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"""The test client could not connect to the veilid-server."""
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pass
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@cache
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def server_info() -> tuple[str, int]:
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"""Return the hostname and port of the test server."""
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VEILID_SERVER = os.getenv("VEILID_SERVER")
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if VEILID_SERVER is None:
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return "localhost", 5959
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hostname, *rest = VEILID_SERVER.split(":")
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if rest:
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return hostname, int(rest[0])
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return hostname, 5959
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async def api_connector(callback: Callable) -> _JsonVeilidAPI:
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"""Return an API connection if possible.
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If the connection fails due to an inability to connect to the
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server's socket, raise an easy-to-catch VeilidTestConnectionError.
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"""
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hostname, port = server_info()
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try:
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return await veilid.json_api_connect(hostname, port, callback)
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except OSError as exc:
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# This is a little goofy. The underlying Python library handles
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# connection errors in 2 ways, depending on how many connections
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# it attempted to make:
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#
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# - If it only tried to connect to one IP address socket, the
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# library propagates the one single OSError it got.
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#
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# - If it tried to connect to multiple sockets, perhaps because
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# the hostname resolved to several addresses (e.g. "localhost"
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# => 127.0.0.1 and ::1), then the library raises one exception
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# with all the failure exception strings joined together.
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# If errno is set, it's the first kind of exception. Check that
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# it's the code we expected.
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if exc.errno is not None:
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if exc.errno == errno.ECONNREFUSED:
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raise VeilidTestConnectionError
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raise
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# If not, use a regular expression to find all the errno values
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# in the combined error string. Check that all of them have the
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# code we're looking for.
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errnos = ERRNO_PATTERN.findall(str(exc))
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if all(int(err) == errno.ECONNREFUSED for err in errnos):
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raise VeilidTestConnectionError
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raise
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